AP Chemistry Unit 1 Study Notes

AP Chemistry 1.1: Moles and molar mass

Use the mole to connect particles, moles, and mass.

Aligned to Atomic Structure and Properties from the current College Board AP Chemistry course outline. Exam weighting for this unit: 7%-9% of the multiple-choice score range listed by College Board.

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These detailed Unit 1 notes were organized from the provided study document. For further study, visit Khan Academy. All Khan Academy content is available for free at www.khanacademy.org.

Overview Open
  • Khan Academy's first topic covers average atomic mass, the mole, Avogadro's number, molar mass, and mole/mass calculations.

1.1 Why Chemists Use Moles Open
  • Atoms and molecules are extremely small.

    • For example, even a tiny amount of water contains an enormous number of H₂O molecules. Counting individual molecules would be impossible.

  • Chemists solve this problem using the mole .

  • A mole is simply a counting unit.

    • Think of:

    • 1 dozen = 12 objects

    • 1 pair = 2 objects

    • 1 mole = 6.022 × 10²³ objects

    • The number

    • 6.022 × 10²³

    • is called Avogadro's number .

  • The objects being counted are usually called representative particles .

  • Depending on the substance, these particles could be:

    • atoms

    • molecules

    • ions

    • formula units

Examples

  • 1 mol He = 6.022 × 10²³ He atoms

    • 1 mol H₂O = 6.022 × 10²³ H₂O molecules

    • 1 mol NaCl = 6.022 × 10²³ NaCl formula units

    • Notice that ionic compounds such as NaCl are usually described in terms of formula units , not molecules.

1.2 Converting Moles to Particles Open

Use:

  • particles = moles × 6.022 × 10²³

Example

  • How many molecules are present in 2.50 mol H₂O?

  • 2.50 mol × (6.022 × 10²³ molecules / 1 mol)

    • = 1.51 × 10²⁴ molecules

  • The unit "mol" cancels.

Important dimensional-analysis idea

  • Set conversions up so unwanted units cancel.

    • For example:

    • 2.50 mol

  • × 6.022 × 10²³ molecules / 1 mol

  • The moles cancel, leaving molecules.

1.3 Converting Particles to Moles Open
  • Reverse the conversion:

    • moles = particles / Avogadro's number

Example

  • A sample contains 3.011 × 10²³ atoms of carbon.

  • 3.011 × 10²³ atoms × (1 mol / 6.022 × 10²³ atoms)

    • = 0.5000 mol C

1.4 Atomic Mass Open
  • The periodic table lists an atomic mass for each element.

    • For example:

    • C ≈ 12.01

    • O ≈ 16.00

    • Cl ≈ 35.45

    • These values normally are not whole numbers because most naturally occurring elements contain multiple isotopes.

  • Atomic mass for individual atoms can be expressed in atomic mass units , written:

    • amu

    • or

    • u

1.5 Isotopes and Average Atomic Mass Open
  • An isotope is a version of an element that has:

    • the same number of protons

    • a different number of neutrons

  • Since the number of protons determines the element, changing neutrons does not change the identity of the element.

    • For example:

  • Carbon-12:

    • 6 protons 6 neutrons

  • Carbon-13:

    • 6 protons 7 neutrons

  • Both are carbon because both contain 6 protons .

  • But their masses differ because they contain different numbers of neutrons.

1.6 Why the Periodic Table Gives Decimal Atomic Masses Open
  • The atomic mass on the periodic table is a weighted average of the masses of an element's naturally occurring isotopes.

  • "Weighted" means more common isotopes affect the average more.

Formula

  • average atomic mass = Σ(isotope mass × fractional abundance)

  • The symbol Σ means "add all of these together."

Example

  • Suppose an imaginary element has:

    • isotope X-10: 80.0%

    • isotope X-11: 20.0%

  • Convert percentages to decimals:

    • 80.0% = 0.800

    • 20.0% = 0.200

    • Then:

    • (10)(0.800) + (11)(0.200)

    • = 8.0 + 2.2

    • = 10.2 amu

    • Notice that 10.2 is much closer to 10 than 11 because isotope X-10 is much more abundant.

AP test shortcut

  • If one isotope is overwhelmingly abundant, the average atomic mass should be closest to that isotope.

  • If your answer is nowhere near the most abundant isotope, check your work.

1.7 Percent Abundance vs. Fractional Abundance Open
  • This mistake is extremely common.

    • If abundance = 25%

    • do not multiply by 25.

  • Convert it to:

    • 0.25

    • Example:

    • (35 amu)(0.75) + (37 amu)(0.25)

    • not:

    • (35)(75) + (37)(25)

1.8 Molar Mass Open
  • Molar mass is the mass of exactly one mole of a substance.

  • Units:

    • g/mol

  • The periodic table gives you the numerical molar mass of an element.

    • Example:

    • Carbon atomic mass ≈ 12.01 amu

    • Carbon molar mass ≈ 12.01 g/mol

    • This means:

  • 1 mol C has a mass of 12.01 g

  • Similarly:

    • 1 mol O ≈ 16.00 g

    • 1 mol Na ≈ 22.99 g

1.9 Molar Mass of a Compound Open
  • To find a compound's molar mass:

  • Identify every element.

  • Find its atomic mass.

  • Multiply by the number of atoms.

  • Add everything together.

    • Example: H₂O

  • H₂O contains:

    • 2 H

    • 1 O

    • Using:

    • H = 1.008 g/mol

    • O = 16.00 g/mol

  • Molar mass:

    • 2(1.008) + 16.00

    • = 18.016

    • ≈ 18.02 g/mol

    • Example: CaCl₂

    • Ca ≈ 40.08

    • Cl ≈ 35.45

  • CaCl₂:

    • 40.08 + 2(35.45)

    • = 40.08 + 70.90

    • = 110.98 g/mol

  • Do not forget the subscript 2.

    • Example: Al₂(SO₄)₃

    • This is harder because of parentheses.

  • Count atoms first:

    • Al = 2

    • S = 3

    • O = 12

    • because:

    • 3 × O₄ = 12 oxygen atoms.

    • Then:

    • 2(26.98) + 3(32.06) + 12(16.00)

    • = 53.96 + 96.18 + 192.00

    • = 342.14 g/mol

1.10 Grams → Moles Open

Use:

  • moles = mass / molar mass

    • or through dimensional analysis:

    • grams × (1 mol / molar mass in grams)

Example

  • How many moles are in 36.0 g H₂O?

  • 36.0 g H₂O × (1 mol H₂O / 18.02 g H₂O)

    • ≈ 2.00 mol H₂O

1.11 Moles → Grams Open

Use:

  • mass = moles × molar mass

Example

  • Find the mass of 3.00 mol CO₂.

  • Molar mass CO₂:

    • 12.01 + 2(16.00)

    • = 44.01 g/mol

    • Then:

    • 3.00 mol × 44.01 g/mol

    • = 132 g CO₂

    • to three significant figures.

1.12 The Most Important Conversion Map Open
  • Memorize this relationship:

    • particles ⇄ moles ⇄ grams

  • Between particles and moles:

    • 6.022 × 10²³ particles = 1 mol

  • Between moles and grams:

    • 1 mol = molar mass in grams

  • You usually cannot directly convert particles to grams .

  • Go through moles:

    • particles → moles → grams

    • or:

    • grams → moles → particles

1.13 Significant Figures Open
  • AP Chemistry calculations often require correct significant figures.

  • For multiplication and division:

  • Your final answer should generally have the same number of significant figures as the measurement with the fewest significant figures .

    • Example:

  • 2.03 kg has 3 significant figures .

    • So a calculated answer based on that measurement would normally be reported using 3 significant figures.

  • Khan Academy's current practice also asks students to calculate molar mass/moles and report answers with appropriate significant figures.

Topic 1: What You Need to Know for a Test Open

Memorize

  • 1 mol = 6.022 × 10²³ particles

    • moles = mass / molar mass

    • mass = moles × molar mass

    • average atomic mass = Σ(mass × fractional abundance)

Understand

  • Why atomic masses are decimals.

  • Why the average atomic mass is closer to the most abundant isotope.

  • Why molar mass connects microscopic particles to measurable mass.

Be able to do

  • grams → moles

    • moles → grams

    • moles → particles

    • particles → moles

    • grams → particles

    • particles → grams

    • calculate molar mass

    • calculate average atomic mass