AP Chemistry Unit 1 Study Notes
AP Chemistry 1.7: Periodic trends
Explain atomic and ionic trends using Coulombic attraction, shielding, and distance.
Aligned to Atomic Structure and Properties from the current College Board AP Chemistry course outline. Exam weighting for this unit: 7%-9% of the multiple-choice score range listed by College Board.
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Source note
These detailed Unit 1 notes were organized from the provided study document. For further study, visit Khan Academy. All Khan Academy content is available for free at www.khanacademy.org.
Overview Open
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Khan Academy's current periodic-trends section covers Coulomb's law, atomic and ionic radii, ionization energy, successive ionization energies, electron affinity, and electronegativity.
The most important thing in AP Chemistry is explaining why trends happen.
7.1 Coulomb's Law Open
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The attraction between charged particles can be understood with Coulomb's law.
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A simplified relationship is:
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F ∝ (q₁q₂)/r²
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where:
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q₁ and q₂ represent charges
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r represents distance between charges.
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For atoms:
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positive nucleus attracts negative electrons.
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Stronger attraction occurs when:
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nuclear charge is greater
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electron is closer to the nucleus
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Weaker attraction occurs when:
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electron is farther away
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shielding reduces the attraction
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Khan Academy directly connects periodic trends to Coulombic attraction.
7.2 Nuclear Charge Open
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More protons mean a larger positive nuclear charge.
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Example:
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C has 6 protons.
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N has 7.
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O has 8.
Moving left → right across a period increases the number of protons.
7.3 Shielding Open
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Inner electrons partially reduce the attraction between outer electrons and the nucleus.
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This effect is called shielding .
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Core electrons lie between:
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the nucleus
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and
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valence electrons.
They partially "shield" the valence electrons from the full nuclear charge.
7.4 Effective Nuclear Charge Open
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An electron experiences a net positive attraction called effective nuclear charge , often written:
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Zeff
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A simplified idea is:
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Zeff ≈ nuclear charge − shielding
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This is not normally used as an exact AP Chemistry calculation. It is mainly a reasoning tool.
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Across a period:
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number of protons increases
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but shielding does not increase as dramatically because electrons are entering the same general shell.
So effective nuclear attraction generally increases.
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7.5 Atomic Radius Open
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Atomic radius describes atomic size.
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Across a period:
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radius generally decreases left → right
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Why?
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More protons are added.
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Electrons are generally added to the same principal energy level.
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The greater effective nuclear attraction pulls the electron cloud closer.
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Therefore:
smaller radius
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7.6 Radius Down a Group Open
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Moving downward:
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atomic radius increases
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Why?
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Each new period adds another electron shell.
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Example:
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Li has outer electrons in n = 2.
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Na has outer electrons in n = 3.
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K has outer electrons in n = 4.
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Additional shells mean:
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valence electrons farther from nucleus
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increased shielding
Therefore the atoms become larger.
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7.7 Atomic Radius Trend Open
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Overall:
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largest → bottom-left
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smallest → top-right
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Think:
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Radius grows:
← and ↓
7.8 Ionic Radius Open
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Forming ions changes atomic size.
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Cations
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Cations are generally smaller than their neutral atoms.
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Example:
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Na⁺ < Na
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Why?
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Na loses its outer 3s electron.
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Na:
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[Ne]3s¹
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Na⁺:
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[Ne]
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The entire third shell is no longer occupied.
Therefore, radius decreases dramatically.
7.9 Anions Open
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Anions are generally larger than their neutral atoms.
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Example:
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Cl⁻ > Cl
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Why?
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Adding an electron increases:
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electron-electron repulsion
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while the number of protons stays the same.
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The electron cloud spreads out more.
7.10 Isoelectronic Species Open
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Isoelectronic species have the same number of electrons.
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Example:
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O²⁻
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F⁻
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Ne
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Na⁺
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Mg²⁺
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Each contains 10 electrons .
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If electron count is identical, compare protons.
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O²⁻: 8 protons
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F⁻: 9
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Ne: 10
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Na⁺: 11
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Mg²⁺: 12
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More protons pull the same number of electrons more strongly.
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Therefore size decreases as proton number increases:
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O²⁻ > F⁻ > Ne > Na⁺ > Mg²⁺
This is extremely useful on AP questions.
7.11 Ionization Energy Open
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Ionization energy is the energy required to remove an electron from a gaseous atom or ion.
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Example:
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Na(g) → Na⁺(g) + e⁻
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Removing an electron requires overcoming the attraction between the electron and nucleus.
7.12 Ionization Energy Across a Period Open
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Generally:
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increases left → right
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Why?
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Effective nuclear attraction increases.
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Electrons are held more tightly.
Therefore more energy is needed to remove one.
7.13 Ionization Energy Down a Group Open
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Generally:
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decreases going down
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Why?
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Outer electrons are:
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farther from nucleus
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more shielded
Therefore they are easier to remove.
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7.14 Ionization Energy Trend Open
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Overall:
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higher toward:
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top-right
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lower toward:
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bottom-left
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So it moves opposite to atomic radius.
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Radius:
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← ↓
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Ionization energy:
→ ↑
7.15 Period-Trend Exceptions Open
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You should not treat periodic trends as perfect rules.
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Some exceptions arise because:
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s and p subshells have different energies
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paired electrons repel each other
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especially stable configurations can occur
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AP questions often care more about whether you can explain experimental values using electron structure than whether you memorized a simple arrow.
7.16 Successive Ionization Energies Open
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Ionization can happen repeatedly.
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IE₁:
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removing first electron
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IE₂:
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removing second
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IE₃:
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removing third
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and so on.
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Generally:
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IE₁ < IE₂ < IE₃ < IE₄...
Each successive electron becomes harder to remove.
7.17 Huge Jumps in Ionization Energy Open
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This is one of the most important Unit 1 skills.
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Imagine:
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IE₁ = 738
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IE₂ = 1451
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IE₃ = 7733
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IE₄ = 10543 kJ/mol
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There is a huge jump:
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between IE₂ and IE₃
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This means:
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the first two electrons are relatively easy to remove.
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After those two valence electrons are gone, the third electron would have to be removed from a much more stable inner shell.
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Therefore:
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the element has 2 valence electrons .
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Khan Academy uses this exact style of reasoning in Unit 1.
7.18 Using Ionization Energies to Find the Group Open
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Huge jump after IE₁:
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→ 1 valence electron
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Huge jump after IE₂:
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→ 2 valence electrons
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Huge jump after IE₃:
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→ 3 valence electrons
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For main-group elements, this can help identify the periodic-table group.
7.19 Electron Affinity Open
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Electron affinity describes the energy change associated with adding an electron to a gaseous atom.
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General idea:
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X(g) + e⁻ → X⁻(g)
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Electron affinity trends are more complicated than radius or electronegativity.
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In general, many atoms toward the right side of a period have a greater tendency to accept electrons, particularly halogens.
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However:
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do not memorize electron affinity as a perfectly smooth trend.
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There are several exceptions.
7.20 Electronegativity Open
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Electronegativity measures how strongly an atom attracts shared electrons in a chemical bond.
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Trend:
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left → right:
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increases
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down a group:
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decreases
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Therefore:
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highest toward top-right
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Fluorine is the most electronegative element.
7.21 Don't Confuse These Three Open
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Ionization energy
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How difficult is it to remove an electron ?
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Electron affinity
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What is the energy change when an isolated gaseous atom gains an electron ?
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Electronegativity
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How strongly does a bonded atom pull shared electrons toward itself ?
These are related but not interchangeable.