Unit 4 Practice: Hard
Chemical Reactions · 20 questions. Try each question before revealing the answer and worked explanation.
Question 1
A particle diagram contains 8 A particles and 5 B particles for:
2A + B → A₂B
How many A₂B particles form, and what remains?
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Answer: 4 A₂B particles form, with 1 B particle left over.
Explanation: Every product requires:
2 A + 1 B
8 A can make:
8 ÷ 2 = 4 products
That uses 4 B.
Since 5 B were available, 1 B remains.
A is the limiting reactant.
Question 2
Why can coefficients be changed when balancing an equation but subscripts cannot?
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Answer: Coefficients change the quantity of each substance, while subscripts change the identity of the substance.
Explanation: Changing:
H₂O → 2H₂O
means two water molecules.
Changing:
H₂O → H₂O₂
creates hydrogen peroxide, a completely different compound.
Question 3
A 10.0 g impure CaCO₃ sample produces 3.52 g CO₂.
Reaction:
CaCO₃ → CaO + CO₂
Determine approximate percent CaCO₃ in the sample.
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Answer: About 80.0%
Work:
Moles CO₂:
3.52 g / 44.01 g/mol ≈ 0.0800 mol
Mole ratio:
1 mol CaCO₃ : 1 mol CO₂
So:
0.0800 mol CaCO₃
Mass CaCO₃:
0.0800 × 100.09 ≈ 8.01 g
Percent:
(8.01 / 10.0)(100) ≈ 80.1%
Question 4
A reaction uses 5.00 g H₂ and 20.0 g O₂.
2H₂ + O₂ → 2H₂O
Determine the limiting reactant and theoretical mass of H₂O.
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Answer: O₂ is limiting; about 22.5 g H₂O form.
Work:
H₂:
5.00/2.016 ≈ 2.48 mol
O₂:
20.0/32.00 = 0.625 mol
0.625 mol O₂ requires:
1.25 mol H₂
More H₂ than that is available, so O₂ is limiting.
Water:
0.625 mol O₂ × 2 = 1.25 mol H₂O
Mass:
1.25 × 18.02 ≈ 22.5 g
Question 5
A gaseous product is collected with known pressure, volume, and temperature. Explain how gas measurements can be used in stoichiometry.
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Answer: Use PV=nRT to find moles of gas, then use the balanced equation's mole ratio.
Explanation: Gas measurements themselves do not directly give stoichiometric amounts.
First:
n = PV/RT
Then use the mole ratio to connect the gas to another reactant or product.
Question 6
Why is the reactant with fewer moles not automatically the limiting reactant?
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Answer: The balanced equation may require different amounts of each reactant.
Explanation: For:
N₂ + 3H₂ → 2NH₃
3 mol H₂ are required for every 1 mol N₂.
So a reactant can have more moles but still be limiting if the reaction requires it in a larger proportion.
Question 7
Determine the oxidation numbers of all elements in H₂SO₃.
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Answer:
H = +1
O = −2
S = +4
Work:
Neutral compound:
2(+1) + S + 3(−2) = 0
2 + S − 6 = 0
S = +4
Question 8
In:
2Fe²⁺ + Cl₂ → 2Fe³⁺ + 2Cl⁻
What is oxidized and what is reduced?
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Answer:
Fe²⁺ is oxidized.
Cl₂ is reduced.
Explanation: Fe:
+2 → +3
It loses electrons.
Cl:
0 → −1
It gains electrons.
Question 9
Identify the oxidizing and reducing agents in Question 8.
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Answer:
Oxidizing agent: Cl₂
Reducing agent: Fe²⁺
Explanation: Cl₂ gets reduced while causing Fe²⁺ to oxidize.
Fe²⁺ gets oxidized while causing Cl₂ to reduce.
Question 10
Balance this reduction half-reaction in acidic solution:
MnO₄⁻ → Mn²⁺
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Answer:
MnO₄⁻ + 8H⁺ + 5e⁻ → Mn²⁺ + 4H₂O
Explanation: Balance O using H₂O:
4 O → add 4H₂O to products.
Balance H:
4H₂O contains 8H → add 8H⁺ to reactants.
Now charges:
Left before electrons:
−1 + 8 = +7
Right:
+2
Add 5e⁻ to the left:
+7 − 5 = +2
Charge is balanced.
Question 11
How can a redox half-reaction balanced in acidic solution be converted to basic solution?
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Answer: Add OH⁻ to both sides to neutralize every H⁺, form H₂O, and then cancel excess water.
Explanation: For every H⁺ present, add the same amount of OH⁻ to both sides.
Then:
H⁺ + OH⁻ → H₂O
Afterward simplify by canceling water if it appears on both sides.
Question 12
An atom's oxidation number changes from +6 to +3. How many electrons are gained?
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Answer: 3 electrons
Explanation: The oxidation number decreases by 3.
Reduction means electron gain.
Therefore the atom gains 3 electrons.
Question 13
Why is an oxidizing agent itself reduced?
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Answer: Because it accepts electrons from another species.
Explanation: The oxidizing agent causes another species to lose electrons.
Those electrons have to go somewhere.
The oxidizing agent gains them and is therefore reduced.
Question 14
For:
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
How many moles H₂SO₄ react with 0.0500 mol NaOH?
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Answer: 0.0250 mol H₂SO₄
Work:
Ratio:
1 mol H₂SO₄ : 2 mol NaOH
So:
0.0500 × 1/2 = 0.0250 mol
Question 15
A 25.0 mL acid sample is titrated with 20.0 mL of 0.150 M NaOH. The acid reacts 1:1 with NaOH. Find acid molarity.
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Answer: 0.120 M
Work:
Moles NaOH:
0.150 × 0.0200 = 0.00300 mol
1:1 ratio:
0.00300 mol acid
Volume acid:
0.0250 L
Molarity:
0.00300 / 0.0250 = 0.120 M
Question 16
Use the same data as Question 15, but the acid reacts with NaOH in a 1:2 ratio.
Find acid molarity.
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Answer: 0.0600 M
Explanation: If:
1 mol acid : 2 mol NaOH
then acid moles:
0.00300 / 2 = 0.00150 mol
Then:
0.00150 / 0.0250 = 0.0600 M
Question 17
What is the difference between endpoint and equivalence point?
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Answer:
Equivalence point: exact stoichiometric reaction point.
Endpoint: observed experimental signal telling you to stop the titration.
Explanation: An endpoint may be an indicator color change.
A good indicator is chosen so its endpoint occurs very close to the true equivalence point.
Question 18
Why is the pH at equivalence not always exactly 7?
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Answer: The products may react with water and make the solution acidic or basic.
Explanation: For strong acid + strong base at 25°C, equivalence is approximately pH 7.
But a weak acid titrated with strong base forms its conjugate base at equivalence.
That conjugate base can react with water and produce OH⁻, making the solution basic.
Question 19
Why is dissolving NaCl in water usually classified as a physical change?
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Answer: The identities of Na⁺ and Cl⁻ remain unchanged.
Explanation: The ionic lattice is disrupted and the ions become hydrated by water.
But no new chemical identities are created.
Evaporating the water can recover NaCl.
Question 20
A gas is observed during an experiment. Why does that observation alone not prove a chemical reaction occurred?
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Answer: Gas can also form from a physical process such as boiling or evaporation.
Explanation: Evidence must be interpreted in context.
Gas formation may suggest a chemical reaction, but it is not absolute proof by itself.
A student should determine whether a new substance actually formed.