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Unit 7 Practice: Medium

Equilibrium · 20 questions. Try each question before revealing the answer and worked explanation.

Question 1

Write Kc for:

N₂(g) + 3H₂(g) ⇌ 2NH₃(g)

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Answer:

Kc = [NH₃]² / ([N₂][H₂]³)

Explanation: Each concentration is raised to its stoichiometric coefficient.

Question 2

Write Kc for:

CaCO₃(s) ⇌ CaO(s) + CO₂(g)

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Answer:

Kc = [CO₂]

Explanation: CaCO₃ and CaO are pure solids, so they are omitted.

Only CO₂ appears.

Question 3

For a reaction, K = 25. What does this suggest?

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Answer: Products are favored.

Explanation: Because K is greater than 1, equilibrium lies more toward products.

It does not mean the reaction goes 100% to completion.

Question 4

For a reaction, K = 2.0 × 10⁻⁶. What does this suggest?

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Answer: Reactants are strongly favored.

Explanation: The very small value means only a relatively small amount of product exists at equilibrium.

Question 5

A reaction has K = 4.0. What is K for the reverse reaction?

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Answer: 0.25

Work:

Kreverse = 1/4.0 = 0.25

Question 6

A reaction has K = 3.0. What is K if the entire equation is doubled?

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Answer: 9.0

Work:

Knew = K²

= 3.0²

= 9.0

Question 7

Reaction 1 has K₁ = 2.0 and Reaction 2 has K₂ = 5.0. If the reactions are added, what is Koverall?

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Answer: 10

Work:

Koverall = K₁K₂

= 2.0 × 5.0

= 10

Question 8

For:

A ⇌ B

K = 4.0.

At some moment:

[A] = 0.50 M [B] = 1.00 M

Find Q and predict the shift.

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Answer: Q = 2.0, so the reaction shifts right.

Work:

Q = [B]/[A]

= 1.00/0.50

= 2.0

Since:

Q < K

the reaction moves toward products.

Question 9

For the same reaction, K = 4.0.

If:

[A] = 0.20 M [B] = 1.20 M

predict the shift.

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Answer: Left

Work:

Q = 1.20/0.20

= 6.0

Since:

Q > K

the reaction shifts toward reactants.

Question 10

For:

A ⇌ B

initially:

[A] = 1.00 M [B] = 0

At equilibrium:

[B] = 0.40 M

Find equilibrium [A].

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Answer: 0.60 M

Explanation: For every 1 mol B formed, 1 mol A is consumed.

A decreases by 0.40 M:

1.00 − 0.40 = 0.60 M

Question 11

Using Question 10, calculate Kc.

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Answer: 0.667

Work:

Kc = [B]/[A]

= 0.40/0.60

= 0.667

Question 12

For:

A ⇌ 2B

initially:

[A] = 1.00 M [B] = 0

If x M of A reacts, what are the equilibrium concentrations?

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Answer:

[A]eq = 1.00 − x

[B]eq = 2x

Explanation: The balanced equation shows that every 1 mole of A produces 2 moles of B.

Question 13

For:

N₂ + 3H₂ ⇌ 2NH₃

What happens if NH₃ is added?

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Answer: The equilibrium shifts left.

Explanation: Adding product creates excess product.

The system responds by consuming some NH₃ and forming reactants.

Question 14

For the same reaction, what happens if H₂ is removed?

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Answer: The equilibrium shifts left.

Explanation: Removing a reactant causes the system to shift toward the side that replaces it.

Question 15

For:

N₂(g) + 3H₂(g) ⇌ 2NH₃(g)

What happens if the container volume decreases?

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Answer: The equilibrium shifts right.

Explanation: Decreasing volume increases pressure.

The left side has:

4 moles gas

The right has:

2 moles gas

The system shifts toward fewer gas particles.

Question 16

For:

H₂(g) + I₂(g) ⇌ 2HI(g)

What happens if volume decreases?

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Answer: No significant shift.

Explanation: There are 2 total moles of gas on each side.

Changing volume affects both sides equally in the ideal model.

Question 17

What happens if an inert gas is added at constant volume?

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Answer: No equilibrium shift.

Explanation: The partial pressures of the reacting gases do not change when volume and temperature remain constant.

The total pressure increases, but equilibrium depends on the reacting species.

Question 18

For an exothermic reaction:

Reactants ⇌ Products + heat

what happens if temperature increases?

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Answer: The equilibrium shifts left.

Explanation: Adding heat is similar to adding a product.

The system shifts toward reactants to consume some of the added heat.

Question 19

For an endothermic reaction:

Reactants + heat ⇌ Products

what happens if temperature increases?

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Answer: The equilibrium shifts right.

Explanation: Heat acts like a reactant.

Adding heat favors the direction that consumes it.

Question 20

Write Ksp for:

AgCl(s) ⇌ Ag⁺(aq) + Cl⁻(aq)

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Answer:

Ksp = [Ag⁺][Cl⁻]

Explanation: The solid is omitted from the equilibrium expression.